No of revolutions made by the electron in one sec in `2^(nd)` orbit of `Be^(3+)`

Options

A. `1.31 xx 10^(16)`
B. `2.13xx10^(16)`
C. `1.23xx10^(15)`
D. `2.68xx10^(14)`

Answer

A

Explanation

No. of revolutions (rps) `=(Z^2)/(n^3) (6.65xx10^(15)) Hz`