Home
Class 11
CHEMISTRY
The total energy of an electron in the f...

The total energy of an electron in the first excited state of hydrogen atom is -3.4eV. What is the kinetic energy of the electron in this state ?

A

2.55 eV

B

4.25 eV

C

11.25 eV

D

19.55 eV

Text Solution

Verified by Experts

The correct Answer is:
D
(d) Energy of photon corresponding to second line to Balmer series for `Li^(2+)` ion
`=(13.6)xx(3)^2 [1/(2^2) - 1/(4^2)] = 13.6 xx (27)/(16) = 22.95 eV`
Energy needed to reject electron from n = 2
level in H - atom `=13.6 xx 1^2 [1/(2^2) - 1/(oo^2)]`
`=(13.6)/(4) eV = 3.4 eV`
`Delta E = 22.95 - 34 = 19 .55 eV`
Promotional Banner

Similar Questions

Explore conceptually related problems

The total energy of an electron in the first excited state of the hydrogen atom is -3.4eV. What is the potential energy of the electron in this state ?

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV. What is the kinetic energy of the electron in this state ?

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV. What is the potential energy of the electron in this state ?

The ground state energy of hydrogen atom is - 13.6eV. The kinetic energy of the electron in this state is:

The energy of electron in the ground state of Hydrogen atom is -13. 6ev. The kinetic energy of the electron is the 4th orbit is

The ground state energy of hydrogen atom is-13.6 eV. What are the kinetic and potential energies of the electron in this state ?

The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?

The value of the energy for the first excited state of hydrogen will be