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Ionisation energy of He^(+) is 19.6 xx 1...

Ionisation energy of `He^(+)` is `19.6 xx 10^(-18)"J atom"^(-1)` The energy of the first stationary state of `Li^(2+)` is 

A

`-4.41 xx 10^(-18) J ."atom"^(-1)`

B

`-4.41 xx 10^(-17) J ."atom"^(-1)`

C

`-4.41 xx 10^(-16) J ."atom"^(-1)`

D

`8.72 xx 10^(-18)J ."atom"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(E_1)/(E_2) = (Z_1^2)/(Z_2^2) xx (n_2^2)/(n_1^2)`
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