The velocity of an electron in excited state of H-atom is `1.093 xx 10^6` m/s, what is the circumference of this orbit?

Options

A. `3.32 xx10^(-10)` m
B. `6.64 xx 10^(-10) `m
C. `13.30xx10^(-10)`
D. `13.28xx10^(-8) m`

Answer

C

Explanation

`v_n = 2.186 xx 10^6 Z/n ` m/sec
`implies 1.093 xx 10^6 = 2.186 xx 10^6 xx 1/n = 2 `
Circumference of the orbit = 3.33 `xx n^2 A^0`