The radius of the first orbit of hydrogen atom is `0.52 xx 10^(-8)` cm. The radius of the first orbit of `He^(+)` ion is `0.26 xx 10^(-x)` cm. Then the value of x is _______

Answer

8

Explanation

`r= (0.52xx10^(-8) xx 1^2)/(2) = 0.26xx10^(-8) cm`