If the Planck's constant `h = 6.6 xx 10^(-34) Js`, the de-Broglie wave length of a particle having momentum of `3.3 xx 10^(-24) kg.ms^(-1)` will be

Options

A. `2xx10^(-10) m`
B. `1xx10^(-15)` m
C. `10^(5)` m
D. `4xx10^(-10) m`

Answer

A

Explanation

`lambda = h/P = (6.6xx10^(-34))/(3.3 xx 10^(-24)) = 2xx10^(-10) m`