The wavelength of the first member of the  Balmer series in hydrogen spectrum is `xÅ`. Then the wave length `("in "Å)` of the first member of Lyman series in the same spectrum

Options

A. `(5)/(27) x `
B. `4/3 x `
C. `(27)/(5) x `
D. `(5)/(36)` x

Answer

A

Explanation

For Lyman series `1/(lambda) = bar(upsilon_2) = R (1/((1)^2) - 1/((2)^2))`
For Balmer series , `bar(upsilon_1) = R (1/((1)^2) - 1/((3)^2))`