the energy of photon is equal to the kinetic energy of a porton,If `lambda_1` is the De-Broglie wavelength of a proton,`lambda_2` the wavelength associated with the proton and if the energt of the protonis E, then `(lamda_1//lambda_2)` is proportional to

Options

A. `lambda_1+ lambda_2` = `lambda_3`
B. `(1)/(lambda_3) = 1/(lambda_1) + 1/(lambda_2)`
C. `lambda_3 = sqrt(lambda_1 lambda_2)`
D. `(2)/(lambda_3) = 1/(lambda_1) + (1)/(lambda_2)`

Answer

B

Explanation

`(E_R - E_Q) + (E_Q-E_P) = (E_R - R_P)`
`1/(lambda_1) + 1/(lambda_2) = 1/(lambda_3)`