The de-Brogilc wavelength of an electron in the first Bohr orbit is

Options

A. `lambda =(1.23)/(sqrt(m))`
B. `lambda = (1.23)/(sqrt(h)) m`
C. `lambda = (1.23)/(sqrtV)` nm
D. `lambda = (1.23)/(V)`

Answer

C

Explanation

`lambda = 1/(sqrt(2xx 1.6 xx 10^(-19) vm))`
`lambda = 1/(sqrt(2xx 1.6 xx 10^(-19) xx v xx 9.11 xx 10^(-31))) = (1.23)/(sqrtV) nm`