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The energy of an electron in the first B...

The energy of an electron in the first Bohr's orbit of a hydrogen atom is `-2.18 xx10^(-18)J`. Its energy in the second orbit would be 

A

`-1.09 xx 10^(-18) J`

B

`-4.36xx10^(-18) J`

C

`-5.45 xx10^(-19) J`

D

`-8.72 xx10^(-18) J`

Text Solution

Verified by Experts

The correct Answer is:
C
`E = (-Z^2)/(n^2) xx 2.018 xx 10^(18) ` J/atom
substitute n=2
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