The uncertainity in momentum of an electron is `1 xx 10^(-5) kg.m//s`. The uncertainity in its position will be `(h = 6.62 xx 10^(-34)kg.m//s)`

Options

A. `1.05 xx 10^(-28)m`
B. `1.05xx10^(-26)` m
C. `5.27xx10^(-30)` m
D. `5.27xx10^(-28)` m

Answer

C

Explanation

`Delta x= h/(4 pi m. Delta V)`