The value of `n_(1)` in Balmer series is

Options

A. it may emit another quantum in Balmer series again
B. it must emit another quantum in ultraviolet region of Lyman series
C. second quatum of wavelength 122nm will be emitted
D. second quantum will be emitted in Paschen series i.e., near infrared region

Answer

B, C

Explanation

Second quantum will be in Lyman sereis because from 2nd shell the electron will fall to first shell or ground state.
`1/(lambda) = R[1/(n_1^2) - 1/(n_2^2)] = 109677 [1/(1^2) - 1/(2^2)]` ,
`lambda = 122 xx 10^(-7) cm = 122 `nm