If the electron in hydrogen atom jumps from the third orbit to second orbit, the wavelength of the emitted radiation is given by `lambda = (36)/(xR)` . Then value of x is

Answer

5

Explanation

`1/(lambda) = R[1/(n_1^2) - 1/n_2^2 ] = R [1/2^2 - 1/(3^2)]`
`1/(lambda) = (5R)/(36) therefore lambda = (36)/(5R)`