An `alpha`-particle and a proton are accelerated from rest by the same potential, thenthe ratio of their de-Broglie wavelength is

Options

A. `sqrt2`
B. `1/sqrt2`
C. `2sqrt2`
D. `2`

Answer

A, B, D

Explanation

`lambda = h/(sqrt(2qVm)) , lambda_(alpha) = h/(sqrt(2xx2xxV xx m_(alpha)))`
`implies lambda_(alpha) = (h)/(sqrt(2xx2xx V xx 4))`
`lambda _P =(h)/(sqrt(2xx1xxVxx m_p)) , lambda_p = (h)/(sqrt(2xx1xxV xx 1))`
`(lambda_p)/(lambda_(alpha)) = sqrt((16)/(2)) implies (lambda_P)/(lambda_(alpha)) = 2sqrt2`