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When electron jumps from higher orbit to...

When electron jumps from higher orbit to lower orbit, then energy is radiated in the form of electro magnetic radiation and these radiations are used to record the emission spectrum Energy of electron may be calculated as `E= (2pi^2 m_e Z^2 e^4)/(n^2 h^2)`
where `m_e` = rest mass of electron `DeltaE = (E_(n_2)- E_(n_1)) = 13.6xxZ^2 xx [1/(n_1^2) - 1/(n_2^2)]`eV per atom
This equation was also used by Rydberg to calculate the wave number of a particular line in the spectrum.
`bar(upsilon) = 1/(lambda) = R_H Z^2 [1/(n_1^2) -1/n_2^2] m^(-1)`
Where , `R_H = 1.1 xx 10^7 m^(-1)` (Rydberg constant)
For Lyman, Balmer, Paschen, Brackett and Pfund series the value of `n_1` = 1,2,3,4,5 respectively and `n_2 = oo` for series limit, If an electron jumps from higher orbit n to ground state than number of spectral line will be `""^nC_2` . Ritz modified the Rydberg equation by replacing the rest mass of electron with reduced mass `(mu)`.
`1/(mu) = 1/(m_N) + 1/(m_e)` , Here `m_N` mass of nucleus , `m_e` = mass of electron.
What will be the value of modified Rydberg.s constant, if the nucleus having mass `m_N` and the electron having mass `m_e` revolve around the centrer of the mass?

A

`R_H xx (m_N)/(m_e)`

B

`R_H xx (m_e)/(m_N)`

C

`R_H xx (m_e)/(m_N + m_e)`

D

`R_H xx (m_N)/(m_N + m_e)`

Text Solution

Verified by Experts

The correct Answer is:
D

`R_H ,(m_N)/(m_N + m_e)`
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