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The number of electrons involved in the ...

The number of electrons involved in the reduction of nitrate ion to hydrazine is ........

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The correct Answer is:
7
`NO_(3)^(-) rarr N_2H_4`
To balance N atoms, multiple `NO_3^(-)` by 2, we have
`2overset(+5)(NO_3^(-))rarroverset(-2)(N_2H_4)`
`{:("Total O.N "= 2x×15 ,"Total O.N" = 2 xx -2),(=+10 ,=-4):}`
To balance O.N. add `14e^(-) " to " ` L.H.S
we have `2NO_(3)^(-)+ 14e^(-) rarr N_2H_4`
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