Which of the following are correct about the reaction, `FeS_(2) + O_(2)rarrFe_(2)O_3 + SO_(2)`

Options

A. E.q. wt. of `FeS_2` is M/11
B. Eq. wt. of `SO_2` is M/5.5
C. S has -2 oxidation state in `FeS_2`
D. 1 mole of `FeS_2` requires 7/4 mole of `O_2`

Answer

A, B, D

Explanation

`2Fe^(2+) rarr (Fe^(3+))_2 +2e` ,
Eq.wt. of `FeS_(2) = (M)/(22//2) = M/11`
`2FeS_(2)+11/2O_(2) rarr 4SO_2 +Fe_(2)O_3`
In this reaction 22 eletrons involved for 4 moles of `SO_2` .
Eq.wt of `SO_(2)=(M)/(22//4) =M/(5.5) `
`O_(2)^(0) +4erarr2(O^(2-))`
has - 1 oxidation state .