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2Mn(2)O7rarr4MnO(2)+ 3O2 (If M is mol. ...

`2Mn_(2)O_7rarr4MnO_(2)+ 3O_2` (If M is mol. wt. of `Mn_(2)O_7`). Find the equivalent, weight of `Mn_2O_7` in the above change.

Text Solution

Verified by Experts

The correct Answer is:
6

`Mn_(2)^(7+) +6 e rarr 2Mn^(4+)`
2 `xx` mole of `Mn_(2) O_(7) =4xx` mole of `MnO_2`
`=4xx3 xx` eq. of `MnO_2 =12 ` eq. of `MnO_2`
`:.` Mole of `Mn_(2)O_(7) = 6 ` eq. of `MnO_2`
`:. ` Eq. of `Mn_(2) O_(7) ` = Eq. of `MnO_7`
`:.` Eq. wt. of `Mn_(2) O_(7) = M//6`
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