The equivalent weight of a species if acts as oxidant or reductant should be derived by: Eq. weight Mol.wt. of oxidant or reductant =`("Mol.w.t of oxidant or reductant")/("Number of electrons lost or gained by onemclecule of oxidant or reductant")` . During chemical reactions, equal all equivalents of one species react with same number of equivalents of other species giving same number of equivalent of products. However this is not true for reactants if they react in terms of moles. Also Molarity can be converted to normality by multiplying the molarity with valence factor or .n. factor
The equivalent weight of an element is 13.16. It forms an acidic oxide which with KOH forms a salt isomorphous with `K_(2)SO_4` The atomic weight of element is :

Options

A. 78.96
B. 52.64
C. 26.32
D. 39.48

Answer

A

Explanation

Isomorphs of `K_(2)SO_(4)` is `K_(2)MO_4`
`:.` Oxide will be `MO_3`
`:.` E.A. =`("at. wt")/("Valency")` (or)
13.16 = at. Wt./6