A solution contains mixture of `H_(2)SO_(4), H_(2)C_(2)O_4` 20 ml of this solution requires 40 ml of M/10 NaOH for neutralization and 20 ml of N/10 `KMnO_4` for oxidation. The molarity of `H_2C_2O_4, H_2SO_4` are

Options

A. ` 0.1, 0.1`
B. `0.1, 0. 05`
C. ` 0.05, 0.1`
D. ` 0.05, 0.05`

Answer

D

Explanation

Let molarity of `H_(2)SO_(4)= M_1 and H_2C_2O_4=M_2`
No. of milli equivalents of `(H_2SO_4+H_2C_2O_4)` = No. of milli equivalent of NaOH
`20(2M_1+2M_2)=40xx1/10`
`40(M_1+M_2)=4`
`M_1+M_2=0.1 " "...(1)`
No.of milli equivalents of `H_(2)C_(2)O_(4)=` No. of mili equivalents `KMnO_4`
`20(2M_2)=20 xx1/10`
`M_(2) =1/20 =0.05 M...(2)`
`M_1 =0.1 -0.05 =0.05M`