A 5.0 mL solution of H2O2 libearates 0....

A 5.0 mL solution of `H_2O_2` libearates 0.508g of iodine from an acidified KI solution. Calculate the strength of `H_2O_2` solution in terms of volume strength at STP.

2.24 .V.

4.48 .V.

8.96 .V.

5.6 .V.

Text Solution

Verified by Experts

The correct Answer is:

`(0.508)/127 =(5xxN)/1000 implies N=0.8`
5.6 xx Normality = Volume strength
`:.` Volume strength `= 5.6 xx 0.08 = 4.48` .V.

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