2 mole, equimolar mixture of `Na_(2)C_(2)O_(4) and H_(2)C_(2)O_(4)` required `V_1 L ` of 0.1 M `KMnO_4` in acidic medium for complete oxidatiion. The same amount of the mixture required `V_2 L` of 0.1 M NaOH for neutralization. The ratio of `V_(1) " to "V_2` is x:y, then the value of x + y is (x and y are integers)

Explanation

No.of moles of `Na_2C_2O_4 =H_(2)C_(2)O_(4)=1`
`4 =v_1 xx0.5 , v_1 =8L`
`2 =v_2 xx0.1 impliesv_(2)=20L`
`v_1:v_2=8:20`
`= 2:5 =x:y , x +y=7`