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0.01 mole of FeSn (iron (II) sulphide) ...

0.01 mole of `FeS_n` (iron (II) sulphide) required 0.06 mole of `AO_(4)^(3-)` for complete oxidation. The species formed are `FeO, SO_2 and A^(2+)` . Calculate the value of n.

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The correct Answer is:
D
`0.01xxn-f =0.06xx3`,
`n-f =18" "18 =(2/n+4)xxn, n =4`
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