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A particle traversed half of the distanc...

A particle traversed half of the distance with a velocity of `V_(0)`.The remaining parts of the distance was covered with velocity `V_(1)`, for half of the time and with `V_(2)` for other half of the time .Find the mean velocity of the particle averahed and the whole time of motion .

Text Solution

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Average velocity for the second half distance `=(v_(1)""t/2+v_(2)""t/2)/(t/2+t/2)=(v_(1)+v_(2))/(2)`
Average velocity for the first half distance `=v_(0)`
Average velocity for total path
`=(2v_(0) ((v_(1)+v_(2))/(2)))/(v_(0)+(v_(1)+v_(2))/(2))= (2v_(0) (v_(1)+v_(2)))/(v_(1)+v_(2)+2v_(0))`
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