The displacement x of a particle at the instant when its velocity v is given by `v = sqrt(3x +16)`. Find its acceleration and initial velocity

Explanation

`v=sqrt(3x+16) or v^(2)=3x+16`
`or v^(2)-16=3x` Comparing with `v^(2)-u^(2)=2aS`.
we get u=4 units, 2a=3 or a=1.5 units.