A body starts from rest and moves with uniform acceleration of `5 ms^(-2)` for 8 seconds. From that time the acceleration ceases. Find the distance covered in 12s starting from rest.

Explanation

The velocity after 8 seconds
`v=0+5 xx 8=40m//s`
Distance covered in 8 seconds
`s_(0)=0+1/2 xx 5+64=160m`
After 8s body moves with uniform velocity and distance covered in 4s with uniform velocity is
`S=vt=40 xx 4=160m`
The distance covered in
12s=160+160=320m