A particle moving along a straight line with initial velocity u and acceleration a continues its motion for n seconds. What is the distance covered by it in the last `n^(th)` second ?

Explanation

`S=ut+1/2 at^2`
Displacement in n seconds `=un +1/2 an^2`
Displacement in (n-1) seconds `=u(n-1)+1/2 a(n-1)^(2)`
Displacement in nth seconds=Displacement in n seconds -displacement in (n-1) seconds.
`S_n=u+a(n-1/2)`