A stone is dropped into a well and the sound of splash is heard after 5.3 sec. If the water is at a depth of 122.5 m from the ground, the velocity of sound in air is

Explanation

If `t_(1)` is the time taken by stone to reach the ground and `t_(2)` the time taken by sound to go up, then `t_(1)+t_(2)=5.33`
Since `s=ut+1/2 at^(2)" "122.5=0t+1/2 xx 9.8 xx t_(1)^(2)`
`t_(1)^(2)=(245)/(9.8)=(2450)/(98)=25" "therefore t_(1)=5s`
`t_(2)=0.33s`
Velocity of sound `=("displacement")/("time")=(122.5)/(0.33)=367m//s`