A balloon starts from rest from the ground and moves with uniform acceleration g/8. When it reaches a height h a ball is dropped from it. Find the time taken by the ball to reach the ground.

Explanation

Velocity of ballon when is at a height is
`v=sqrt((2gh)/(8)=sqrt(gh)/2`
`-h=vt-1/2gt^(2)`
`-h=sqrt(gh)/2 t-1/2gt^2`

`-h=sqrt(gh)/2 t-1/2 gt^(2)`
`1/2 gt^(2)-sqrt(gh)/2 t-h=0`
Simplifying and taking only the positive value as negative value of t is not acceptable we get `t=2 sqrt(h/g)`