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The displacement of two particles execut...

The displacement of two particles executing S.H.M are represented by `y_(1) = a sin(wt + phi)` and `y_(2) = a cos w t`. The phase difference between the velocities of these particles is

A

`-phi`

B

`+phi`

C

`phi + pi//2`

D

`phi - pi//2`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • The displacement of two particles executing S.H.M are represented by y_(1) =a sin(wt + phi) and y_(2)=a cos omegat . The phase difference between the velocities of these particles is

    A
    `-phi`
    B
    `+phi`
    C
    `phi + pi//2`
    D
    `phi - pi//2`

  • The displacement of a particle in S.H.M is in opposite phase with

    A
    Velocity
    B
    Acceleration
    C
    Amplitude
    D
    Frequency

  • The displacement of a particle in S.H.M is in opposite phase with

    A
    Velocity
    B
    Acceleration
    C
    Amplitude
    D
    Frequency

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    The displacement of two identical particles executing SHM are represented by equations x_(1)= 4sin(10t+ (pi)/(6)) and x_(2) =5 cosomega t For what value of omega energy of both the particles is same

    The displacement of a particle in S.H.M is in opposite phase with

    The displacement of two identical particles executing SHM are represented by equations x_(1)=4sin(10t+(pi)/2) and x_(2)=5cos (omegat) . For what value of omega , energy of both the particles is same.

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    The displacement of two identical particles executing SHM are represented by equations x_(1)=4sin( 10t + (pi)/(2)) & x_(2) = 5 cos(omegat) . For what value of omega , energy of both the particles is same.

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