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A particle executes linear simple harmon...

A particle executes linear simple harmonic motion wit an amplitude of 3 cm. When the particle is at, 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

A

`(2pi)/(sqrt(3))`

B

`(sqrt(5))/(pi)`

C

`(sqrt(5))/(2pi)`

D

`(4pi)/(sqrt(5))`

Text Solution

Verified by Experts

The correct Answer is:
D
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