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A liquid flowing from a vertical pipe ha...

A liquid flowing from a vertical pipe has a very definite shape as it flows from the pipe. To get the equation for this shapes assume that the liquid is falling under gravity once it leaves th pipe. Just as it leaves the pipe, the liquid has speed `V_(0)` and the radius of the stream of liquid is `r_(0)`
Speed (V)of the liquid as a function of the distance .y. it has fallen is given by

A

`V=sqrt(V_(0)^(2)+2gy)`

B

`V=sqrt(V^(2)+2gy)`

C

`V=sqrt(V_(0)^(2)-gy)`

D

`V=sqrt(V_(0)^(2)-2gy)`

Text Solution

Verified by Experts

The correct Answer is:
A
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