The distance between the tew slits in a Young's double slit experiment is d and the distance of the screen from the plane of the slits is b, P is a point on the screen directly infront of one of the slits. The path difference between the waves arriving at P from the two slits is

Options

A. `(d^2)/(b)`
B. `(d^2)/(2b)`
C. `(2d^2)/(b)`
D. `(d^2)/(4b)`

Answer

B