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A circular coil of 500 turns of wire has...

A circular coil of 500 turns of wire has an enclosed area of 0.1 `m^(2)` per turn. It is kept perpendicular to a magnetic field of induction 0.27 and rotated by `180^(@)` about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 `Omega`.

Text Solution

Verified by Experts

`q=(phi_(i)-phi_(f))/(R)=(NBA-(-NBA))/(R)=(2NBA)/(R)`
`q=(2 xx 500 xx 0.2 xx 0.1)/(50)` = 0.4 C.
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A circular coil of 500 turns of wire has an enclosed area of 0.1m^2 per turn. It is kept perpendicular to a magnetic field of induction 0.27 and rotated by 180^@ about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50Omega

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Knowledge Check

  • A circular coil of 500 turns of wire has an enclosed area of 0.1 m^2 per turn. It is kept perpendicular to a magnetic field of induction 0.2T and rotated by 180^@ about a diameter perpendicular to the field in 0.1 sec. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 ohms.

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