The self-inductance of a coil having 200 turns is 10 milli henry. Calculate the magnetic flux through the cross-section of the coil corresponding to current of 4 milliampere. Also determine the total flux linked with each turn.

Explanation

Total magnetic flux linked with the coil,
`N phi=LI=10^(-2) xx 4 xx 10^(-3)=4 xx 10^(-5)` Wb
`:.` Flux per turn, `phi=(4 xx 10^(-5))/(200)=2 xx 10^(-7)`Wb