Find the kinetic energy, potential energy and total energy in first and second orbit of hydrogen atom if potential energy in first orbit is taken to be zero.

Explanation

`E_(1)=-13.60eV,K_(1)=-E_(1)=13.60eV`
`U_(1)=2E_(1)=-27.20eV`
`E_(2)=-3.40eV" "K_(2)=3.40eV` and
`U_(2)=-6.80eV`
Now, `U_(1)=0`, i.e., potential energy has been increased by 27.20eV. So, we will increase U and E in all energy states by 27.20eV while kinetic energy will remain unchanged. Hence `K(eV),U(eV),E_(eV)` First orbit are 13.6, 0, 13.6 in Second orbit 3.40, 20.40, 23.80