The binding energies per nucleon for deuteron `(._1H^2)` and helium `(._2He^4)` are 1.1 MeV and 7.0 MeV respectively. Calculate the energy released, when two deuterons fuse to form a helium nucleus.

Explanation

The fusion reaction is `2(._1H^2) to ._2He^4 +Q`
Q=Total binding energy of the product `._2He^4` -Total binding energy of reactant i.e., two deuterons.
=4 x 7.0 - 4 x 1.1 = 28.0 -4.4 =23.6 MeV