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Binding energy per Nucleon of 3^(Li^7) ...

Binding energy per Nucleon of `3^(Li^7)` and `2^(He^4)` are 5.6MeV and 7.06 MeV. Then find the energy of proton in the following reaction `._3Li^7 + P to 2 ._2He^4`

A

1.728 MeV

B

17.28 MeV

C

172.8 MeV

D

1728 MeV

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The correct Answer is:
B
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