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Light of wavelength lambda in air enters...

Light of wavelength `lambda` in air enters medium of refractive index μ. If two points in this medium lie along the path of this light at a distance x, then phase difference `phi_(0)` between these two points is

A

`phi_(0) =1/n ((2pi)/(lambda_(0)))x`

B

`phi_(0) = n ((2pi)/(lambda_(0)))x `

C

`phi_(0) = (n-1) ((2pi)/(lambda_(0)))x `

D

`phi_(0) = 1/((n-1)) ((2pi)/(lambda_(0)))x `

Text Solution

Verified by Experts

The correct Answer is:
B
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