Home
Class 12
PHYSICS
Nucleus A decays to B with decay constan...

Nucleus A decays to B with decay constant `lamda_(1)` and B decuys to C with decay constants `lamda_(2)`. Initially at t=0, number of nuclei of A and B are `2N_(0)` and `N_(0)` respectively. At some instant `t=t_(0)`, number of nuclei of B stop changing. Find `t_(0)` if at this intant number of nuclei of B is `(3N_(0))/(2)`

A

`(1)/(lamda_(1))ln[(4lamda_(1))/(3lamda_(2))]`

B

`(1)/(lamda_(2))ln[(4lamda_(1))/(3lamda_(2))]`

C

`(lamda_(1)+lamda_(2))ln[(4lamda_(1))/(3lamda_(2))]`

D

`(1)/(lamda_(1))ln[(4lamda_(1))/(3lamda_(2))]`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE LEVEL-II (LECTURE SHEET (ADVANCED)) More than one correct answer Type Questions )|4 Videos

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE LEVEL-II (LECTURE SHEET (ADVANCED)) Linked Comprehension Type Questions Passage-I :)|2 Videos

  • NUCLEAR PHYSICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL-I (MAIN)) (Straight Objective Type Questions)|10 Videos

  • MOVING CHARGES AND MAGNETISM

    AAKASH SERIES|Exercise EXERCISE-III|45 Videos

  • NUCLEI

    AAKASH SERIES|Exercise Practice Exercise|40 Videos

Similar Questions

Explore conceptually related problems

At time t = 0 , number of nuclei of a radioactive substance is 100. At t = 1 s this number becomes 90. Find the number of nuclei at t = 2s.