यदि n एक पूर्णांक है तो lim(xto n+)(x-[n...

यदि n एक पूर्णांक है तो `lim_(xto n+)(x-[n])=`

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यदि lim(xto0)[1+In(1+b^(2))]^(1//x)=2bsin^(2)theta, bgt0 तथा theta eps...
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lim(x→0)((a^(x)-b^(x))/x)=
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lim(xto0){(sinx-x+(x^(3))/6)/(x^(5))}=
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lim(nto oo){1/(n^(2))+2/(n^(2))+3/(n^(2))+…………+n/(n^(2))} है
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lim(xto0)[1/x-(log(1+x))/(x^(2))]=
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lim(ntooo)[(sumn^(2))/(n^(3))]=
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