Home
Class 11
PHYSICS
Two blocks m(1)=4 kg and m(2)=2 kg conne...

Two blocks `m_(1)=`4 kg and `m_(2)=2` kg connected by a weightless rod on a plane having inclination of `37^(@)` the coefficient of friction of `m_(1)` and `m_(2)` with the inclined plane are `mu=0.25` each. Then the common accleration of the two blocks and the tension in the rod are

Promotional Banner

Similar Questions

Explore conceptually related problems

Two blocks m_(1) = 4 kg and m_(2) = 2 kg connected by a weightless rod slide down a plane having an inclination of 37^(@) . The coefficient of dynamic friction of m_(1) and m_(2) with the inclined plane are mu_(1) = 0 .75 and mu_(2) = 0 . 25 respectively Find the common acceleration of the two blocks and tension in the rod Take is 37^(@) = 0.6 and cos 37^(@) = 0 .8 .

Two blocks of masses m_1 = 4 kg and m_2 = 2kg connected by a massless rod slide down on an inclined plane of inclination 37^o as shown in figure. If coefficient of friction of m_1 and m_2 with inclined plane are mu_1 = 0.75 and mu_2 = 0.25 respectively, then tension (T) in the rod is (g = 10 ms^-2 )

Two blocks of masses m, = 4 kg and m, = 2 kg connected by a massless rod slide down on an inclined plane of inclination 37 degree as shown in figure. If coefficient of friction of m_1 and m_2 with inclined plane are mu_1 = 0.75 and mu_2 = 0.25 respectively, then tension (T) in the rod is (g = 10 ms^-2)

Two blocks of masses m_(1)=1 kg and m_(2)=2 kg are connected by a string and side down a plane inclined at an angle theta=45^(@) with the horizontal. The coefficient of sliding friction between m_(1) and plane is mu_(1)=0.4, and that between m_(2) and plane is mu_(2)=0.2. Calculate the common acceleration of the two blocks and the tension in the string.

Two blocks of masses m_(1)=1 kg and m_(2)=2 kg are connected by a string and side down a plane inclined at an angle theta=45^(@) with the horizontal. The coefficient of sliding friction between m_(1) and plane is mu_(1)=0.4, and that between m_(2) and plane is mu_(2)=0.2. Calculate the common acceleration of the two blocks and the tension in the string.

Two blocks of masses m_(1)=1 kg and m_(2)=2 kg are connected by a string and side down a plane inclined at an angle theta=45^(@) with the horizontal. The coefficient of sliding friction between m_(1) and plane is mu_(1)=0.4, and that between m_(2) and plane is mu_(2)=0.2. Calculate the common acceleration of the two blocks and the tension in the string.

A rod of mass M and length L lies on an incline having inclination of theta = 37^(@) . The coefficient of friction between the rod and the incline surface is mu = 0.90 . Find the tension at the mid point of the rod.

The coefficient of friction between m_(2) and inclined plane is mu (shown in the figure). If (m_(1))/(m_(2))=sin theta then

The coefficient of friction between m_(2) and inclined plane is mu (shown in the figure). If (m_(1))/(m_(2))=sin theta then