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Calculate the pressure exerted by one gr...

Calculate the pressure exerted by one gram of helium present in a 5 L vessel at room temperature?

Text Solution

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The ideal gas equation is given as, PV = nRT
Number of moles = n = 0.25
R + Universal gas constant = 0.0821 L atm `K^(-1) "mol"^(-1)`
V = Volume = 5 lit
Pressure exerted by helium gas ` = P = (nRT)/(V) = (0.25 xx 0.0821 xx 298)/(5) = 1.224 " atm" = 930 "torr"`
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