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CH(3)-overset(CH(3))overset("| ")unders...

`CH_(3)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")"C "-underset(OH)underset("| ")"CH"CH_(3)overset("Conc. "H_(2)SO_(4))rarr "A(predominant)".` A is

A

`CH_(3)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")"C "-CH=CH_(2)`

B

`CH_(3)-CH=CH-CH_(2)-CH_(3)`

C

`CH_(3)-overset(CH_(3))overset("| ")"C "=underset(CH_(3))underset("| ")"C "-CH_(3)`

D

`CH_(3)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")"C "-overset(SO_(3)H)overset("| ")"CH"-CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_(3)-overset(CH_(3))overset("| ")underset(CH_(3))underset("| ")"C "-overset(OH)overset("| ")"CH"-CH_(3)overset("Conc. "H_(2)SO_(4))underset(Delta)rarr CH_(3)-overset(CH_(3))overset("| ")"C "=underset(CH_(3))underset("| ")"C "-CH_(3)`
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