As per hardy-schulze formulation, the flocculation values of the following for haemoglobin sol are in the order

Options

A. `AlCl_(3)gtK_(3)[Fe(CN)_(6)]gtK_(2)CrO_(4)gtKBr=KNO_(3)`
B. `K_(3)[Fe(CN)_(6)]ltK_(2)CrO_(4)ltKBr=KNO_(3)=AlCl_(3)`
C. `K_(3)[Fe(CN)_(6)]gtAlCl_(3)gtK_(2)CrO_(4)gtKBr gtKNO_(3)`
D. `K_(3)[Fe(CN)_(6)]ltK_(2)CrO_(4)ltAlCl_(3)ltKBr lt KNO_(3)`

Answer

B

Explanation

Haemoglobin is a positive charged sol.
So, flocculation power will be in the order
`[Fe(CN)_(6)]^(-3)gt CrO_(4)^(-2)gtBr^("Ѳ")=NO_(3)^("Ѳ")=Cl^("Ѳ")`