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The molar solubility of Cd(OH)(2) is 1.8...

The molar solubility of `Cd(OH)_(2)` is `1.84xx10^(-5)M` in water. The expected solubility of `Cd(OH)_(2)` in a buffer solution of pH = 12 is

A

`1.84xx10^(-5)M`

B

`(2.49)/(1.84)xx10^(-9)M`

C

`6.23xx10^(11)M`

D

`2.49xx10^(-10)` M

Text Solution

Verified by Experts

The correct Answer is:
D
`pH=12 harr pOH=2implies[OH^("Ѳ")]=10^(-2)M`
`Cd(OH)_(2)to underset(s)(Cd^(+2))+underset(2s)(2OH^("Ѳ"))`
`K_(sp)=4s^(3)=4xx(1.84xx10^(-5))^(3)" "=24.9xx10^(-15)M^(3)`
Now, in buffer solution, `" "[OH^("Ѳ")]=10^(-2)`
`[Cd^(+2)]=(K_(sp))/([OH^("Ѳ")]^(2))=(24.9xx10^(-15))/(10^(-4))=24.9xx10^(-11)M`
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