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The radius of gyration of a uniform rod ...

The radius of gyration of a uniform rod of length l , about an axis passing through a point `(l)/(8)`away form the centre of the rod , and perpendicular to it is:

A

`l/4`

B

`l/64`

C

`sqrt((19)/(192))l`

D

`sqrt(7/48)l`

Text Solution

Verified by Experts

The correct Answer is:
C
`I=(Ml^(2))/12+(Ml^(2))/64, Ml^(2)[19/192]`
`Mk^(2)=M(l^(2)19)/192,k=sqrt(19/192)l`
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