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Visible light of wavelenght 8000 xx 1...

Visible light of wavelenght `8000 xx 10^(-8)` cm falls normally on a single slit and produces a diffraction pattern. It is found that the Third diffraction minimum is at `45^(@)` from the central maximum. If the first minimum is produced at `theta_(1)` then `theta_(1) ` is close to :

A

`40^(@)`

B

`35^(@)`

C

`30^(@)`

D

`15^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`a sin theta_(2)=3 lamda, a sin theta_(1)=lamda`
`(sin theta_(1))/(sin theta_(2))=1/3impliessin theta_(1)=(sin theta_(2))/3=(sin 45^(@))/3=1/(2sqrt(3))impliestheta_(1)~~15^(@)`
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