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A parabola is drawn with focus at (3,4) ...

A parabola is drawn with focus at (3,4) and vertex at the focus of the parabola `y^2-12y-4y+4=0`. The equation of the parabola is

A

`x^(2)-6x-8y+25=0`

B

`y^(2)-8x-4y+28=0`

C

`x^(2)-6x+8y-25=0`

D

`x^(2)-4x-8y+28=0`

Text Solution

Verified by Experts

The correct Answer is:
A
`y^(2)-12x-4y+4=0`
`(y-2)^(2)=12x`
Vertex is (0,2) and a=3
Its focus =(3,2)
Hence the vertex of required parabola is (3, 2) and focus is (3, 4)
So, required parabola is `(x-3)^(2)=4(b)(y-2)`
`rArr x^(2)-6x-8y+25=0`
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