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The term independent of x in (1+x+x^(-2)...

The term independent of x in `(1+x+x^(-2)+x^(-3))^(10)` is n then the last digit of `(n+2)^(n)` is

A

1

B

3

C

7

D

9

Text Solution

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The correct Answer is:
To solve the problem of finding the term independent of \( x \) in the expression \( (1 + x + x^{-2} + x^{-3})^{10} \) and then determining the last digit of \( (n + 2)^n \), where \( n \) is the coefficient of that term, we can follow these steps: ### Step 1: Identify the expression We start with the expression: \[ (1 + x + x^{-2} + x^{-3})^{10} \] ### Step 2: Rewrite the expression We can rewrite the terms involving negative powers of \( x \): \[ 1 + x + \frac{1}{x^2} + \frac{1}{x^3} = 1 + x + x^{-2} + x^{-3} \] This can be rewritten as: \[ 1 + x + \frac{1 + x^3}{x^2} \] ### Step 3: Find the constant term To find the term independent of \( x \), we need to consider the expansion of the expression. The term independent of \( x \) occurs when the powers of \( x \) sum to zero. ### Step 4: Use the multinomial expansion Using the multinomial theorem, we can express the expansion: \[ (1 + x + x^{-2} + x^{-3})^{10} \] We need to find combinations of the terms that yield a total power of \( x^0 \). ### Step 5: Set up the equation Let \( a \), \( b \), \( c \), and \( d \) be the number of times we choose \( 1 \), \( x \), \( x^{-2} \), and \( x^{-3} \) respectively. We have: \[ a + b + c + d = 10 \] The power of \( x \) in the term is given by: \[ b - 2c - 3d = 0 \] ### Step 6: Solve the equations From \( b - 2c - 3d = 0 \), we can express \( b \) in terms of \( c \) and \( d \): \[ b = 2c + 3d \] Substituting this into the first equation gives: \[ a + (2c + 3d) + c + d = 10 \] This simplifies to: \[ a + 3c + 4d = 10 \] ### Step 7: Find integer solutions We need to find non-negative integer solutions for \( a + 3c + 4d = 10 \). We can try different values for \( d \) and solve for \( a \) and \( c \). 1. **If \( d = 0 \)**: \[ a + 3c = 10 \quad \Rightarrow \quad (10, 0), (7, 1), (4, 2), (1, 3) \] This gives us 4 solutions. 2. **If \( d = 1 \)**: \[ a + 3c = 6 \quad \Rightarrow \quad (6, 0), (3, 1), (0, 2) \] This gives us 3 solutions. 3. **If \( d = 2 \)**: \[ a + 3c = 2 \quad \Rightarrow \quad (2, 0) \] This gives us 1 solution. 4. **If \( d \geq 3 \)**: No solutions since \( 4d > 10 \). ### Step 8: Count the total solutions Adding the solutions: - For \( d = 0 \): 4 solutions - For \( d = 1 \): 3 solutions - For \( d = 2 \): 1 solution Total solutions = \( 4 + 3 + 1 = 8 \). ### Step 9: Calculate \( n \) Thus, the coefficient \( n \) of the term independent of \( x \) is \( 8 \). ### Step 10: Find the last digit of \( (n + 2)^n \) Now we need to calculate: \[ (n + 2)^n = (8 + 2)^8 = 10^8 \] The last digit of \( 10^8 \) is \( 0 \). ### Final Answer The last digit of \( (n + 2)^n \) is \( \boxed{0} \).

To solve the problem of finding the term independent of \( x \) in the expression \( (1 + x + x^{-2} + x^{-3})^{10} \) and then determining the last digit of \( (n + 2)^n \), where \( n \) is the coefficient of that term, we can follow these steps: ### Step 1: Identify the expression We start with the expression: \[ (1 + x + x^{-2} + x^{-3})^{10} \] ...
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